A Certian Ammeter Has a Resistance of on a Scale Which Reads Up to Chegg
Electrical Circuits Review
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Role B: Multiple Choice
8. If an electric circuit was coordinating to a h2o park, then the battery would be analogous to the ____.
a. pipes which bear the h2o through the water excursionb. pump which supplies energy to motion the h2o from the ground to a high elevation
c. the people which flow from the summit of the water ride to the bottom of the water ride
d. the rate at which water is pumped onto the slide
e. the change in potential free energy of the riders
f. the summit of the water slide
k. the bottom of the water slide
h. the long lines which exist at the park
i. the speed at which riders motion every bit they slide from the top to the lesser of the ride
Answer: B
A h2o ride at a water park is coordinating to an electric circuit. Get-go of all, there is an entity which flows - water flows in a h2o park and (in conventional terms) + charge flows in an electric circuit. In each case, the fluid flows spontaneously from a loftier energy location to a low energy location. The flow is through pipes (or slides) in a water park and through wires in an electric circuit. If the pipes or the wires are broken, then there can be no continuous flow of fluid through the circuit. A consummate loop is required to establish the circuit.
This catamenia of fluid - whether of water or charge - is possible when a pressure level difference is created between two locations in the excursion. In the water park, the pressure difference is the difference in water force per unit area created by 2 locations of unlike heights. Water flows spontaneously from locations of loftier pressure (high distance) to locations of low force per unit area (depression altitude). In an electric excursion, the electric potential difference betwixt the ii terminals of a battery or energy source provides the electrical pressure which presses on charge to motion them from a location of high pressure (high electric potential) to a location of depression pressure (low electrical potential).
Energy is required to motion the fluid uphill. In a h2o park, a water pump is used to do work upon the water in order to raise it from the low top back up to the high superlative. The h2o pump does not supply the h2o; the water which is already in the pipes. Rather, the h2o pump supplies the free energy to pump the water from the location of low free energy and low force per unit area to the location of high energy and high pressure. In an electric circuit, the battery is the charge pump which pumps the charge through the bombardment from the location of depression electric potential energy (the - final) to the location of high electric potential free energy (the + terminal). The bombardment does not supply the electric accuse; the charge is already in the wires. The battery simply supplies the energy to exercise piece of work on the charge in pumping it uphill.
9. If an electric circuit was analogous to a water park, then the positive last of the battery would be analogous to the ____.
a. pipes which carry the water through the water circuitb. pump which supplies energy to movement the water from the basis to a high top
c. the people which menstruum from the superlative of the water ride to the bottom of the h2o ride
d. the rate at which water is pumped onto the slide
e. the change in potential energy of the riders
f. the top of the h2o slide
g. the bottom of the water slide
h. the long lines which exist at the park
i. the speed at which riders move as they slide from the acme to the bottom of the ride
Answer: F
A water ride at a water park is coordinating to an electric circuit. First of all, there is an entity which flows - water flows in a water park and (in conventional terms) + charge flows in an electrical circuit. In each case, the fluid flows spontaneously from a loftier energy location to a low energy location. The flow is through pipes (or slides) in a h2o park and through wires in an electrical circuit. If the pipes or the wires are broken, then there can be no continuous menstruation of fluid through the excursion. A consummate loop is required to institute the circuit.
This catamenia of fluid - whether of h2o or charge - is possible when a pressure level difference is created between two locations in the circuit. In the water park, the pressure departure is the difference in water pressure created by two locations of dissimilar heights. Water flows spontaneously from locations of high force per unit area (high altitude) to locations of low pressure (low altitude). In an electric circuit, the electrical potential difference between the two terminals of a battery or free energy source provides the electric force per unit area which presses on charge to move them from a location of high pressure (high electric potential) to a location of low force per unit area (low electrical potential).
Energy is required to move the fluid uphill. In a water park, a h2o pump is used to practice piece of work upon the h2o in order to enhance it from the low height back up to the loftier height. The h2o pump does non supply the water; the water which is already in the pipes. Rather, the h2o pump supplies the energy to pump the water from the location of low free energy and depression pressure to the location of high free energy and high pressure level. In an electric circuit, the bombardment is the charge pump which pumps the charge through the battery from the location of low electrical potential energy (the - terminal) to the location of high electrical potential energy (the + terminal). The battery does non supply the electric charge; the charge is already in the wires. The battery just supplies the energy to practise work on the charge in pumping it uphill.
10. If an electric circuit was coordinating to a h2o park, and then the electric electric current would be analogous to the ____.
a. pipes which conduct the h2o through the water circuitb. pump which supplies free energy to motion the water from the ground to a high meridian
c. the people which menses from the acme of the water ride to the bottom of the h2o ride
d. the rate at which water is pumped onto the slide
e. the change in potential energy of the riders
f. the top of the h2o slide
yard. the lesser of the water slide
h. the long lines which exist at the park
i. the speed at which riders move as they slide from the top to the bottom of the ride
Respond: D
The flow of h2o at a h2o park is analogous to the flow of charge in an electric circuit. The charge per unit at which accuse moves past a point on a excursion as measured in Coulombs of accuse per second (or some comparable set of units) is known as the electric current. In our illustration, the fluid which flows is water and the rate at which the fluid passes any given bespeak is the electric current.11. The potential energy possessed per unit of accuse at any given location is referred to as the electric ___.
a. current
b. resistance
c. potential
d. power
Answer: C
This is the definition of electric potential - a concept you should internalize.
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12. Ane ampere is the amount of current that exists when ____ flows by a certain point in a conductor in ____.
a. i watt; one second
b. i joule; i hour
c. one electron; i second
d. 1 electron; one 60 minutes
e. one volt; 1 second
f. ane volt; one 60 minutes
thou. i coulomb; one second
h. i coulomb; ane hr
Answer: G
An ampere is a unit of electric current. And electrical current is defined as the rate at which charge moves by a signal on a circuit every bit measured in standard units of Coulombs of charge per second.
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13. If half dozen coulombs of charge flow by point 'A' in a circuit in four seconds, and so ____ coulombs of charge volition flow past point 'A' in 8 seconds.
a. 0.67
b. 1.5
c. 2
d. 3
e. 4
f. 6
g. 8
h. 12
i. 24
Answer: H
The current (I) is the quantity of charge flowing past a signal (Q) in a given amount of time (t). That is, I = Q/t. And so in this case, the electric current at bespeak A is (6 C) / (4 s) or 1.5 amperes. Thus the Q/t ratio is 1.5 regardless of the time. So solve the equation
for Q to obtain the reply.
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xiv. In which of the following situations will the light bulb light? List all that apply.
Answer: DF
For a excursion to be established, in that location must be a airtight conducting loop from the positive final to the negative final. This would mean that circuits D, E and F would all exist circuits. But in order for the light bulb to light, it must be included every bit part of the electric circuit. So in E, the bulb does not low-cal since the loop does non extend upwards into and through the lite bulb; accuse would simple flow out of the + terminal bombardment and directly dorsum into - terminal the battery.
A simple circuit containing a battery and a calorie-free bulb is shown in the diagram at the right. Use this diagram to answer the next several questions.
fifteen. The current through the battery is ___.
a. greater than that through the lite seedling
b. less than that through the light seedling
c. the same as that through the light bulb
d. greater than that through each wire
e. less than that through each wire
Answer: C
Charge is a conserved quantity; it is never gained nor lost. In an electric circuit, the charge present in the wires and conducting elements is what moves through the circuit. This accuse is enclosed in the wires and unable to escape (assuming in that location is no fault in the circuit). As the charge flows, it does not accumulate in a given location. And accuse is not used up as though it were a consumable quantity. Nor is charge transformed into another type of entity. Given all this reasoning, one would conclude that the electric current at one location in an electric excursion is the same equally the current at any other location in an electric excursion.
sixteen. Accuse flowing through this circuit is most energized at ____. Cull the one best answer.
a. the + final of the bombardmentb. the - concluding of the battery
c. merely prior to entering the low-cal bulb
d. just afterward exiting the lite seedling
east. ... nonsense! The energy of the charge is the aforementioned everywhere throughout the circuit.
Answer: A
The + terminal of the bombardment is the high energy terminal of the battery.
17. The role or purpose of the battery in this circuit is to ____. Choose three.
a. supply electric charge so that a current can existb. supply energy to the charge
c. motion the charge from the - to the + terminal of the battery
d. transform energy from electrical energy into light energy
e. establish an electric potential departure between the + and - terminals
f. replenish the charge which is lost in the calorie-free seedling
yard. offer resistance to the period of charge so that the light seedling can go hot
Answer: BCE
To plant an electric circuit, accuse must be moved from low energy to high free energy. In one case at high energy, the accuse spontaneously flows through the conducting wires and other conducting elements of the circuit back downwards to the low energy terminal. A battery'due south role is to supply the energy which is required to motion the charge from the - last to the + terminal of the battery. Past placing a big quantity of like charge at one location, an electric pressure or potential difference is established, forcing the like charges to move away from this location to the location of opposite charge (the - last).
18. A 12-Volt battery would supply ___. List all that use.
a. 3 Coulombs of charge with 4 Joules of energyb. 4 Coulombs of charge with iii Joules of energy
c. 12 Coulombs of charge with 1 Joule of energy
d. 1 Coulomb of charge with 12 Joules of energy
due east. 0.5 Coulombs of accuse with 24 Joules of free energy
f. 24 Coulombs of charge with 2 Joules of free energy
Reply: D
Electric potential (or voltage) is divers equally the electric potential energy per charge. Information technology is the Joules of free energy per coulomb of accuse possessed past some quantity of charge at some location in an electrical circuit. A 12 Volt battery moves some quantity of accuse from the - terminal to the + terminal, giving the accuse energy. Each coulomb of charge would acquire 12 Joules of energy. The energy/accuse ratio would exist 12 J/C.
19. The charges that flow through the wires in your home ____.
a. are stored in the outlets at your domicileb. are created when an appliance is turned on
c. originate at the power (energy) company
d. originate in the wires between your abode and the power company
east. already exist in the wires at your dwelling
Respond: E
This question targets a mutual misconception about electric circuits. The misconception presumes that the role of the electrical outlet, the battery, or the power company is to provide the charge required to move through the home. But the ability company is simply the source of the energy required to ready the charge in motion by the institution of an electric potential departure. The charge itself is present in the wires and conducting elements of your dwelling house in the class of mobile electrons.
twenty. Approximately how long would it take an electron to travel from the bombardment of a car to a head light and back (complete loop)?
a. seconds
b. hours
c. years
d. i-millionth of a second
e. one-10th of a second
Reply: B
Electrical accuse globe-trotting through an electric circuit moves at a rather slow step. Quite surprising to many, the distance traversed per unit of time is on the order of i meter per hr.
21. The electric circuit shown at the right consists of a bombardment and 3 identical light bulbs. Which of the following statements are true apropos this circuit? List all that utilize.
a. The current through indicate X will be greater than that through point Z.b. The current through point Z will be greater than that through point Y.
c. The current will be the aforementioned through points Ten, Y and Z.
d. The current through point X will be greater than that through indicate Y.
e. The current through point Y will be greater than that through point X.
Reply: C
Every bit discussed in Question #xv in a higher place , the current in an electrical circuit is everywhere the same. Then the current at these three locations is the same.
a. The electric potential difference between X and Y is more than that between Y and Z.b. The electric potential difference between 10 and Z is more than that between Y and W.
c. The electric potential difference between X and Y is the same every bit that between Y and Z.
d. The electric potential difference between Ten and Z is the same every bit that between Y and W.
e. The electric potential deviation between Y and W is more than that betwixt Ten and Y.
Answer: DE
The electrical potential difference across a light bulb (or any resistor) in an electric circuit is simply the product of the current at that bulb multiplied by the resistance of the bulb. Each bulb has the same resistance (since they're identical) and the same electric current (since the current is everywhere the same). So the electrical potential difference across each seedling is the same. And the potential drop beyond whatsoever two consecutive bulbs is the same. And the potential driblet across two bulbs would be greater than that across one bulb.
a. Conventional current is directed through the external circuit from point 10 to Y to Z to W.b. Conventional current is directed through the external excursion from point W to Z to Y to Ten.
c. Conventional current is directed through the internal excursion from indicate W to point X.
d. Conventional electric current is directed through the internal excursion from bespeak 10 to point Westward.
e. The point where accuse possesses the least amount of electric potential energy is point Westward.
Respond: ACE
The battery is referred to as the internal circuit. Charge moves in the internal circuit from the - concluding to the + terminal (in the management from Westward towards Z). The wires and low-cal bulbs comprise the external circuit; accuse moves through the external circuit from the + concluding to the - terminal (in the direction of X to Y to Z to Due west).
24. Voltage ____ an electric circuit.
a. goes through
b. is expressed across
c. is constant throughout
d. is the rate at which charges move through
Respond: B
Voltage or electrical potential is not a thing which moves. Thus, choices A and D are not the answers since they imply move of voltage. And the voltage or electrical potential of a accuse is not something which is constant throughout the excursion as option C suggests.
Voltage or electric potential is a measure out of how energized a quantity of charge is at a given location relative to the - final. Information technology is ofttimes expressed as a divergence beyond two points. Perhaps you have noted this linguistic communication of "the potential across ..." in several of the answers in this Review.
25. 2 or more than of the following words and phrases mean the same affair. Identify them by listing their letters.
a. Voltage
b. Wattage
c. Electric Potential Difference
d. Rate at which charge flows
due east. Electrical Pressure
f. Energy
Answer: ACE
The voltage or electrical potential departure are synonymous terms. Voltage is non synonymous with energy. While voltage (or electric potential difference) is a measure of how energized a quantity of charge is at a given location, voltage is expressed as the free energy per accuse (and non just as free energy). Drawing from the analogy between a water park and an electric excursion, voltage is a mensurate of the quantity of electric pressure placed upon a charge in inducing it to move from one location to another location.
Wattage is synonymous with power. Current is synonymous with the rate at which accuse flows.
26. A loftier voltage battery can ____.
a. do a lot of work on each charge information technology encountersb. do a lot of work over the course of its lifetime
c. button a lot of charge through a circuit
d. last a long time
Answer: A
Voltage refers to the free energy/charge. A battery rated with a high voltage can do a lot of work per every Coulomb of charge which it encounters. Information technology may or may non be able to do a lot of work over its lifetime, depending upon the size of the battery.
27. Which one of the following occurs when a rechargeable battery is recharged?
a. The battery, which has run out of watts, has its wattage restored.b. The battery, which has run out of amps, has current placed back into it.
c. The battery, which has run out of accuse, has charge returned to it.
d. The bombardment, which has run out of chemical reactants, has its chemicals reformed.
Answer: D
Batteries perform their energy-supplying tasks past using the energy from an exothermic oxidation-reduction reaction to do work upon charge within the electric circuit. When a battery no longer works, its reactants are consumed to the point that the electrical potential which the reactants are capable of producing is small compared to the overall resistance of the excursion. At such an instant in time, the ability to induce a current is limited to the indicate that the external circuit elements are no longer functional.
Non all batteries are rechargeable. Those that are rechargeable can accept the products transformed back into reactants. The recharger utilizes electrical energy from an outlet to contrary the previously exothermic reaction, turning its products back into reactants.
28. Birds can safely stand on high voltage electric power lines. This is because ____.
a. they are at low potential with respect to the footing.b. they offer no resistance to current.
c. they ever choose power lines that are non in use.
d. the potential difference betwixt their feet is low.
e. they are perfect insulators.
f. they are perfect conductors.
Answer: D
In order for charge to flow betwixt ii locations, in that location must exist an electric potential difference established betwixt those ii locations. If a bird places its left foot on an electric power line and his correct foot a few centimeters abroad on the aforementioned electrical power line, then there is lilliputian to no divergence in potential between his 2 anxiety. Without an electric potential difference, accuse volition not catamenia through the bird and the bird is condom.
29. When the light seedling in your lamp no longer works, it is because the bulb has _____.
a. run out of energy and can no longer pump chargeb. run out of voltage and must be recharged
c. run out of electrons and then there is no more current
d. burned all of its watts and can no longer shine
east. tripped a circuit breaker and must exist stock-still at the fuse box
f. a broken filament which has resulted in an open up circuit
g. ... nonsense! The bulb is fine; your family just needs to fully pay their power bill.
Answer: F
The nigh mutual cause for the disability of a light bulbs to light is a cleaved filament. A coiled wire of tungsten stretches between two vertical supports. If disturbed while hot or if overworn, the tungsten metallic can break and leave a gap between the ii vertical supports. This gap represents a break in the circuit; a closed conducting loop is no longer established and charge volition not flow.
thirty. A battery is needed in the circuit of your flashlight then that ____.
a. charge is provided to the wiresb. the energy of the low-cal is balanced by the battery
c. an exothermic, light-creating reaction is possible
d. an electric potential difference is maintained beyond the circuit
e. electrons are supplied in guild to light the bulb
Answer: D
One of the roles of a battery is to simply establish a divergence in electrical potential between its two terminals. Charge at the high potential volition flow through the external excursion to the low potential location.
31. When you turn on the room lights, they low-cal immediately. This is best explained by the fact that ____.
a. electrons move very fast from the switch to the light bulb filamentb. electrons nowadays everywhere in the circuit motion instantly
Answer: B
Electrons move very slowly from one location to some other location. But once a excursion is closed, they start moving immediately. While electrons move about a meter or in an hour, the actual bespeak which tells them to start moving can travel at the speed of light. Then once the switch is turned on, a signal is circulated throughout the circuit to get-go the electrons marching. The electrons present in the filament of the excursion.
32. The drift velocity of mobile charge carriers in electric circuits is ____.
a. very fast; less than but very close to the speed of liteb. fast; faster than the fastest motorcar but nowhere near the speed of low-cal
c. boring; slower than Michael Jackson runs the 220-meters
d. very slow; slower than a snail
Answer: D
Drift velocity is the distance which a charge moves per unit of time. This value is very pocket-size since electrons motility very, very slowly. Moving at nearly 1 meter per hour, they are literally slower than a snail.
33. Suppose that the electric current in a typical circuit (DC) is large. This is an indication that ____.
a. the mobile charge carriers are moving very fastb. a large number of mobile charge carriers are moving forwards per 2nd
c. both a and b are true
Answer: B
Current (the rate at which charge moves past a signal on the circuit) and drift velocity (the altitude a accuse moves in a 2d) should not be confused (and ofttimes are). If a current is large, i tin can be sure of only ane thing: a lot of charges are moving forward past a point on the circuit every 2nd.
34. Which of the following statements represent correct unit equivalencies? Listing all that utilize.
a. one Ampere = one Coulomb / second
b. i Joule = 1 Volt / Coulomb
c. 1 Watt = 1 Joule • second
d. 1 Watt = 1 Volt • Coulomb / second
e. 1 Joule / Ohm = i Ampere • Coulomb
f. 1 Joule • Ohm = 1 Volt2 • 2d
Respond: ADEF
This question requires a knowledge of both units for electric quantities and the equations which chronicle those quantities.
In choice a, an Ampere is a unit of electric current (I) and a Coulomb/2nd is a unit of charge per unit of time (Q/t). This is consistent with the equation I = Q/t.
In choice b, a Joule is a unit of energy (E) and a Volt / Coulomb is a unit of voltage per unit of charge (V/Q). Since voltage is the energy per charge, we would expect that energy would be equivalent to voltage • charge. Thus, it is incorrect to equate units of energy to units of voltage per charge.
In option c, a Watt is a unit of measurement of power (P) and a Joule•second is a unit of energy (Eastward) multiplied past a unit of time (t). Simply power is energy / time and not energy • time so this is non a correct unit equivalency.
In option d, a Watt is a unit of measurement of ability (P). On the right side, a Volt is a unit of measurement of voltage (Five) and a Coulomb / second is a unit of current (I). Then since P = I • V, this is a right unit equivalency.
In choice east, a Joule / Ohm is a unit of energy per unit of measurement of resistance (E / R). An Ampere • Coulomb is a unit of electric current multiplied by a unit of measurement of charge (I • Q). Thus, the equation is suggesting that Due east / R = I • Q. This can be rearranged algebraically to say that East / Q = I • R. Since voltage is the free energy per charge (E / Q), the equation can be rewritten equally V = I • R. This is thus a correct unit equivalency.
In choice f, a Joule• Ohm is a unit of measurement of energy multiplied by a unit of resistance (Due east • R). A Volttwo / second is a unit of voltage2 multiplied by a unit of measurement of time (Vtwo • t). Then this equation is suggesting that East • R = V2 • t. This can be rearranged algebraically to say that East / t = Vtwo / R. The right side of the equation is equivalent to power, so the equation tin be rewritten as P = 52 / R. Since this is a correct way of writing the power equation, the given unit equivalency is correct.
35. Which of the following diagrams represents resistors connected in in series? List all that use.
Answer: B
A and C correspond parallel connections equally shown by the branching which occurs before and after the resistors. There is no branching in option B so information technology is a series connection of resistors.
36. These ii resistors are connected in ____.
a. series
b. parallel
c. neither
Answer: A
One can start at the positive terminal of the battery and brainstorm tracing their finger along the wire. If in that location is ever a point where the wire comes to a junction and branches in two or more than directions, then the circuit has a parallel connectedness. Otherwise, information technology is a series circuit. In this diagram, there is no branching. Thus, information technology is a series circuit.
37. The electric potential difference (voltage drop) across each resistor is ___ Volts.
a. 6
b. 12
c. 24
d. ... nonsense!. The electric potential divergence is dependent upon the actual resistance of the resistors
Answer: A
38. If a third resistor (R3), identical to the other two, is added in series with the offset ii, and then the overall resistance will ____ and the overall current will ____.
a. increase, increase
b. decrease, decrease
c. increase, decrease
d. decrease, increase
e. increase, remain the same
f. decrease, remain the same
g. remain the aforementioned, increase
h. remain the aforementioned, decrease
i. remain the aforementioned, remain the aforementioned
Answer: C
Increasing the number of resistors in a series circuit will increase the overall resistance of that circuit and cause the current to decrease. (The opposite is true of a parallel circuit.)
39. If a tertiary resistor (R3), identical to the other 2, is added in series with the first 2, then the electric potential difference (voltage drib) across each of the 3 individual resistors will ____.
a. increment
b. decrease
c. remain the same
Answer: B
Using the same reasoning as in Question #37, nosotros can say that the accuse will acquire 12 Volts in moving through the battery. It will take to lose this 12 volts in iii steps as it passes through the external circuit. Since in that location are now three voltage drops in the external circuit instead of the original two, each drib must be smaller than before. Then there will be a 4-Volt drib through each resistor (instead of the original 6-Volt drop).
The diagram at the correct shows two identical resistors - R1 and R2 - placed in a circuit with a 12-Volt bombardment. Utilise this diagram to reply the side by side several questions.
40. These two resistors are continued in ____.
a. series
b. parallel
c. neither
Reply: B
I can start at the positive terminal of the battery and begin tracing their finger along the wire. If there is e'er a indicate where the wire comes to a junction and branches in two or more than directions, and so the circuit has a parallel connection. Otherwise, it is a series circuit. In this diagram, in that location is some branching. One time the charge reaches the branching point, information technology will either pass through the resistor in the left branch (Rone) or through the resistor in the right co-operative (R2). Thus, it is a parallel circuit.
41. The electrical potential difference (voltage drop) across each resistor is ___ Volts.
a. half dozen
b. 12
c. 24
d. ... nonsense!. The electrical potential difference is dependent upon the actual resistance of the resistors
Answer: B
Accuse receives an increase in electrical potential of 12 volts when moving through the internal circuit (the 
42. If a 3rd resistor (R3), identical to the other 2, is added in parallel with the first two, and then the overall resistance will ____ and the overall current will ____.
a. increment, increase
b. decrease, decrease
c. increment, subtract
d. decrease, increase
e. increase, remain the aforementioned
f. subtract, remain the same
yard. remain the same, increase
h. remain the same, decrease
i. remain the aforementioned, remain the aforementioned
Answer: D
Adding an identical resistor in a separate co-operative will provide more pathways past which charge can traverse through the loop of the circuit. This would be the equivalent of adding some other booth at a toll station on a tollway in parallel with an existing booth. Opening upwards another lane for traffic will reduce the overall resistance and cause an increase in the car flow rate. The aforementioned occurs with charge in parallel circuits. More branches means less resistance and an increased electric current.
43. If a third resistor (Riii), identical to the other two, is added in parallel with the first two, then the electrical potential deviation (voltage drop) across each of the three individual resistors will ____.
a. increase
b. decrease
c. remain the aforementioned
Reply: C
The electrical potential departure across any branch is equal to the voltage of the battery. Calculation a new branch can modify the overall resistance and the overall current, simply information technology does non modify the electric potential difference across the battery nor across the branches.
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44. The resistance of a charge-carrying conducting wire will increment every bit the ____. Cull all that utilise.
a. length of the wire is increasedb. cantankerous-sectional area of the wire is increased
c. temperature of the wire is increased
d. voltage impressed beyond the ends of the wire is increased
e. wire is placed closer and closer to the + terminal of the excursion
Answer: AC
Resistance of a wire increases with increasing length and (to a smaller extent) with increasing temperature. Increasing wire length increases the number of atom-accuse collisions and thus the amount of resistance. Increasing the temperature increases the resistivity of the cloth and thus increases the overall resistance.
45. When plugged into a 120-Volt outlet, a light seedling consumes 300 joules of energy over a 5 second time period. The power of the light seedling is ____ Watts.
a. 0.0167
b. 0.fifty
c. 2.0
d. two.50
e. 60
f. 600
thousand. 1500
h. 7200
Answer: E
Ability is only the rate at which energy is supplied to a excursion or transformed past a excursion. In this case, the power is the energy consumed per time.
46. A sure electrical excursion contains a bombardment, wires and a lite bulb. If potential energy is gained past charges at the battery location, so charges lose potential energy ____.
a. in the wires onlyb. in the bulb only
c. every bit in the wires and the bulb
d. mostly in the wires but a piffling in the bulb
e. mostly in the bulb simply a little in the wires
f. nowhere
Answer: E
Charge volition lose energy every bit they pass through locations of resistance. When in series, locations of greatest resistance will transform electrical energy into other forms at a greater rate. Then free energy will be lost in the light bulb and in the wires to a much lesser extent.
47. A loftier resistance calorie-free bulb and a low resistance light bulb are continued in series to a half-dozen-Volt pack of batteries. Which of the ii low-cal bulbs volition polish the brightest?
a. They will have the same effulgence.b. The low-R bulb will shine more than brightly.
c. The high-R seedling will polish more brightly.
d. There is no fashion to make such a prediction since seedling brightness is contained of seedling resistance.
Respond: C
Since the 2 light bulbs are in serial, the same current (i) is experienced by each. The ability volition be given by the itwo•R product. Since i is the same for each light bulb, the bulb with the greatest resistance will have the greatest power. So the high-R calorie-free bulb will transform electrical energy into light free energy at the greatest charge per unit and thus shine most brightly.
48. A high resistance low-cal bulb and a low resistance lite bulb are connected in parallel and powered by a 6-Volt pack of batteries. Which of the two low-cal bulbs will shine the brightest?
a. They volition have the same brightness.b. The low-R bulb will shine more than brightly.
c. The high-R seedling volition shine more than brightly.
d. There is no fashion to brand such a prediction since seedling brightness is indepenent of seedling resistance.
Answer: B
Since the 2 light bulbs are in parallel, the same voltage drop (V) is experienced by each. The power will exist given by the iii•R product. Since V is the aforementioned for each light bulb, the bulb with the greatest resistance will accept the lest current. Current is of the greatest importance in determining the power of the calorie-free bulb since information technology is squared in the equation. So the low-R light bulb will take the greatest current and thus transform electrical free energy into lite energy at the greatest rate; it will shine virtually brightly.
a. increase the resistance of one of the bulbsb. increment the resistance of two of the bulbs
c. decrease the resistance of two of the bulbs
d. increase the voltage of the battery
east. decrease the voltage of the battery
f. remove 1 of the bulbs
Answer: CDF
The current in a series circuit (both full current and current through individual resistors) is directly dependent upon the bombardment voltage and inversely dependent upon the total circuit resistance. This current can be increased by increasing the battery voltage. It can besides be increased by decreasing the total resistance. Removing a bulb would decrease the total resistance and decreasing the resistance of any private bulb would decrease the total resistance.
a. increase the resistance of one of the bulbsb. increment the resistance of two of the bulbs
c. decrease the resistance of two of the bulbs
d. increase the voltage of the battery
e. decrease the voltage of the bombardment
f. remove one of the bulbs
Reply: CD
Point P represents the location where the full current of this parallel circuit can be measured. The total current would vary direct with the total voltage and inversely with the total resistance. Increasing the battery voltage would increase the electric current at location P. Decreasing the total resistance would increase the current at location P. The total resistance tin can exist decreased by adding some other resistor in a separate branch or by decreasing the resistance of any of the branches.
a. increase the resistance of bulb Xb. subtract the resistance of bulb X
c. increase the resistance of bulb Z
d. subtract the resistance of bulb Z
east. increase the voltage of the battery
f. decrease the voltage of the battery
thousand. remove bulb Y
Answer: CF
The current in seedling Z is dependent upon the voltage drop across seedling Z and the resistance of bulb Z. In equation form,
An increase in battery voltage would increase the voltage drop across bulb Z (VZ) and thus provide a greater current through the bulb. A decrease in the resistance of bulb Z would also increase the current through the bulb. However, making a change in bulb X or Y would have no result on the VZ / RZ ratio.
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